4 ) Consider the chemical equation : CuC * l_{2} + 2; aNO 3 Cu(NO 3 ) 2 +2 What is the percent yield of NaCl if 31.0 g of 21.2 g of NaCl ? CuC * l_{2} reacts with excess NaN * O_{3} to produce a ) 49.7 7 \% b ) 58.4 % ) 63.6 \% d ) 78.8 \%
Sorry but I can't make heads or tails of your question. I THINK the equation is as follows and I know you want percent NaCl; however, I can't figure out what you mean by the numbers.
CuCl2 + 2NaNO3 ==> Cu(NO3)2 + 2NaCl