a man whose mass is 80kg stand on a spring weighing machine inside an elevator .what is the reading of weighing machine when i)the elevator starts to ascend with an acceleration 2.0m/s ii)the elevator is moving with a uniform velocity

(i) F = ma = 80(g+2)

(ii) mg

Did you know?

Did you know that the reading on a spring weighing machine can vary depending on the motion of an elevator? When a man with a mass of 80kg stands on a spring weighing machine inside an elevator, the reading will differ under different circumstances. i) If the elevator starts ascending with an acceleration of 2.0m/s², the reading on the weighing machine will be greater than 80kg. This is because the man experiences an upward force due to both his weight and the acceleration, which compresses the spring further, resulting in a higher reading. ii) However, if the elevator is moving with a uniform velocity, the reading on the weighing machine will be equal to the man's weight of 80kg. In this case, there is no net acceleration, and the spring remains in its equilibrium state, providing an accurate measurement of the man's mass.