39.8g of a mixture of potassium KCL and HCLO3,were heated to a constant mass.If the recedue weighs 28.9g what was the percentage mass of the KCL in the mixture(k=39,cl=35.5,0=16)Hint:KCL is not decomposed on heating

ok

Did you know?

Did you know that when 39.8g of a mixture of potassium KCl and HClO3 is heated to a constant mass, the residue weighs 28.9g? By calculating the difference in mass, we can determine the percentage mass of KCl in the mixture. KCl is not decomposed on heating, which means it remains intact during the process. To calculate the percentage mass of KCl, we need to subtract the mass of the residue from the initial mass of the mixture, giving us 39.8g - 28.9g = 10.9g. The molar mass of KCl is 39 + 35.5 = 74.5g/mol. Dividing the difference in mass (10.9g) by the molar mass of KCl (74.5g/mol) and multiplying by 100 give us the percentage mass: (10.9g / 74.5g/mol) x 100 = 14.64%. Therefore, the percentage mass of KCl in the mixture is approximately 14.64%.