Two dozens of eggs and a loaf of bread cost k17.50. Half a dozen eggs and two loaves of bread cost k14.00. Find:
1.the cost of a dozen eggs.
2.the cost of a loaf of bread.
2d + b = 17.50
d/2 + 2b = 14.00
solve as usual.
Little more specific please 🙏
well, b = 17.50 - 2d
so to find the price of a dozen eggs, solve
d/2 + 2(17.50-2d) = 14.00
can you handle that?
To find the cost of a dozen eggs and the cost of a loaf of bread, let's assign variables to represent the unknown quantities. Let's say the cost of a dozen eggs is E and the cost of a loaf of bread is B.
From the given information, we know two equations:
1. Two dozens of eggs and a loaf of bread cost k17.50:
2E + B = 17.50
2. Half a dozen eggs and two loaves of bread cost k14.00:
0.5E + 2B = 14.00
To solve for E and B, we can use either substitution or elimination method. Let's use the elimination method:
Multiply the second equation by 4 to eliminate the fractions:
4(0.5E + 2B) = 4(14.00)
2E + 8B = 56.00
Now we have the equations:
2E + B = 17.50 ---(1)
2E + 8B = 56.00 ---(2)
Subtract equation (1) from equation (2) to eliminate E:
2E + 8B - (2E + B) = 56.00 - 17.50
7B = 38.50
B = 38.50 / 7
B ≈ k5.50
Substitute the value of B into equation (1):
2E + 5.50 = 17.50
2E = 17.50 - 5.50
2E = 12.00
E = 12.00 / 2
E = k6.00
Therefore, the cost of a dozen eggs is k6.00 and the cost of a loaf of bread is k5.50.