Air pressure decreases during a storm. The difference between the normal air pressure 'n' and the air pressure during the 1935 Florida Keys hurricane was greater than 121 millibars.
Which inequality could be used to find the normal air pressure in the Florida Keys before the hurricane? I answered n - 892 > 121
Using the inequality from Q4, what was the normal air pressure in the Florida Keys before the storm.
(Simply, write the number you get for 'n' when you solve.)
I need help on this one ^
please someone help meeee
the inequality looks good, assuming the pressure was 892 millibars
n - 892 > 121
n > 1013
To find the normal air pressure in the Florida Keys before the hurricane, we can use the inequality n - 892 > 121. To solve for n, we need to isolate it on one side of the inequality.
n - 892 > 121
To isolate n, we need to move the constant term (-892) to the other side of the inequality by adding 892 to both sides:
n > 121 + 892
Simplifying this expression, we get:
n > 1013
So, the normal air pressure in the Florida Keys before the storm would be greater than 1013 millibars.