A spinner is divided into five equal sections labeled 1, 2, 3, 4, and 5. Another spinner is divided into two equal sections labeled A and B. Nigel will spin each spinner one time.
How many of the possible outcomes have a number less than 3 or an A?
2*2 + 1*5 = 9
To determine the number of outcomes that have a number less than 3 or an A, we need to consider the possible outcomes for each spinner separately and then combine the results.
Spinner 1: There are 5 possible outcomes labeled 1, 2, 3, 4, and 5. Out of these, the numbers less than 3 are 1 and 2.
Spinner 2: There are 2 possible outcomes labeled A and B. We are interested in the outcome A.
To find the total number of outcomes that satisfy the given condition, we need to add the number of outcomes in each spinner together.
Number of outcomes less than 3 in Spinner 1 = 2
Number of outcomes A in Spinner 2 = 1
Total number of outcomes that have a number less than 3 or an A = 2 + 1 = 3
Therefore, there are 3 possible outcomes that have a number less than 3 or an A.
To find the number of outcomes that have a number less than 3 or an A, we need to count the number of outcomes that satisfy either of these conditions.
Let's break it down into two parts:
Part 1: Number less than 3
There are two sections on the first spinner (labeled 1 and 2) that have a number less than 3. So, there are 2 possible outcomes on the first spinner.
Part 2: A
The second spinner has two sections (labeled A and B), and we want to count the number of outcomes that have an A. Since there is only one section labeled A, there is only 1 possible outcome on the second spinner.
To find the total number of outcomes that satisfy either condition, we add the outcomes from each part:
Total outcomes = outcomes from Part 1 + outcomes from Part 2
Total outcomes = 2 + 1
Total outcomes = 3
Therefore, there are 3 possible outcomes that have a number less than 3 or an A.