for f(x)=x^2+x and g(x)=2/x+3 find (f-g)(2),(f/g)(1),g^2(3),(gof)(1),(gog)(3),(fog)(1)

Assuming the usual carelessness with parentheses, I'll guess you meant

g(x) = 2/(x+3)
just plug and chug.
(f-g)(x) = f(x) - g(x) = (x^2+x) - 2/(x+3)
So (f-g)(2) = 6 - 2/5 = 28/5
(g◦f)(x) = g(f(x)) = 2/(f(x)+3) = 2/(x^2+x+3)
So (g◦f)(1) = 2/5
Or, f(1) = 2
g(f(1)) = g(2) = 2/5
Do the others in like wise.
Post your work if you get stuck.