to divide the function f(x-1) by (x2+2x-3), we find that the quotient is Q(x) and the remainder is (x+6). If f(0)=a and f(-4)=b, what is the value of b/a?
You said:
f(x-1) = (x^2 + 2x - 3)(Q(x)) + (x+6)
f(0) ---> I replaced x-1 with 0, so x = 1
f(0) = (1+2-3)(Q(x)) + (1+6) = a
so a = 7
f(-4) ----> I replaced x-1 with -4, so x = -3
f(-4) = (9 - 6 - 3)(Q(x)) + -4+6 = b
b = 2
then b/a = 2/7