Find the area of the region bounded by the graphs of the equations y^2=7x and y=mx , where m is a positive constant.
The graphs intersect at (0,0) and (7/m^2,7/m)
so using vertical strips of width dx, the area is
∫[0,7/m^2] (√(7x) - mx) dx = 49/(6m^3)
or, using horizontal strips of width dy,
∫[0,7/m] (y/m - y^2/7) dy = 49/(6m^3)