if you have a supply of 0.50M Ca(NO3)2 solution in your laboratory. How many milliliters of this solution do you have to evaporate to get 32.8g of solid Ca(NO3)2
Another way but not any better.
molar mass Ca(NO3)2 = 40 + (14 + 48)*2 = 164 so 0.5M = 164/2 or 82 g/L.
82 g/L x ?L = 32.8
To find the volume of the solution to evaporate, we need to calculate the amount of Ca(NO3)2 in the given solution.
Step 1: Determine the molar mass of Ca(NO3)2.
Ca(NO3)2 = 1(Ca) + 2(NO3) = 1(40.08) + 2(14.01 + 3(16.00)) = 164.09 g/mol
Step 2: Convert the given mass of Ca(NO3)2 to moles.
32.8 g / 164.09 g/mol = 0.20 mol Ca(NO3)2
Step 3: Use the molarity to calculate the volume of the solution.
0.50 M means 0.50 moles of Ca(NO3)2 in every 1 liter of solution.
0.50 moles/L * 1 L/1000 mL = 0.00050 moles/mL
Step 4: Calculate the volume of the solution required.
0.20 mol Ca(NO3)2 / 0.00050 moles/mL = 400 mL
Therefore, you will need to evaporate 400 mL of the 0.50 M Ca(NO3)2 solution to obtain 32.8 g of solid Ca(NO3)2.
To find the number of milliliters to evaporate, we need to calculate the concentration (Molarity) of the Ca(NO3)2 solution and use it to determine the volume needed for a specific amount of solute.
Here's how to calculate it:
1. Determine the molar mass of Ca(NO3)2:
- Ca: 1 atom x 40.08 g/mol = 40.08 g/mol
- N: 2 atoms x 14.01 g/mol = 28.02 g/mol
- O: 6 atoms x 16.00 g/mol = 96.00 g/mol
Molar mass of Ca(NO3)2:
40.08 g/mol + 28.02 g/mol + 96.00 g/mol = 164.10 g/mol
2. Calculate the moles of Ca(NO3)2 needed:
moles = mass / molar mass
moles = 32.8 g / 164.10 g/mol
3. Determine the volume of the solution needed (in liters):
Molarity (M) = moles / volume (L)
0.50 M = moles / volume (L)
Rearrange the equation to isolate the volume:
volume (L) = moles / Molarity
volume (L) = (32.8 g / 164.10 g/mol) / 0.50 M
4. Convert the volume to milliliters:
1 L = 1000 mL
volume (mL) = volume (L) x 1000 mL/L
Now, calculate the volume:
volume (mL) = [(32.8 g / 164.10 g/mol) / 0.50 M] x 1000 mL/L
By plugging in the values, we'll get the answer.
how many moles of Ca(NO3)2 in 32.8g? If it is x, then since 0.50M solution has 0.5 moles per liter, you will need 2x liters of solution.
or, 2000x mL