WRITE IONIC EQUATION OF :
H2CO3(AQ)+2NH3(AQ) ====> (NH4)2CO3(AQ)
H2CO3(aq) + 2NH3(aq) ====> 2(NH4)^+(aq) + (CO3)^2-(aq)
NOTE: I looked on the web and found answers all over the place so don't trust everything you see on the web. What I have written here is correct.
After I posted the above I did some more digging. Here is an interesting article that I thought you might like to read.
//newscenter.lbl.gov/2014/10/22/new-insights-on-carbonic-acid-in-water/
This article, written by researchers @ UC Berkeley, claim that about 1% of a CO2/H2O mixture forms H2CO3 and in 300 ns that forms H^+ and HCO3^-. No Ka values are given. Also, I found that "anhydrous" H2CO3 can be made and that is stable @ cryogenic temperatures but that doesn't apply to your question since you specifiy H2CO3(aq). Without a Ka value for that ionization to H^+ and HCO3^- I'll stick by my initial answer.
To write the ionic equation for the reaction:
Step 1: Write the balanced molecular equation:
H2CO3(aq) + 2NH3(aq) → (NH4)2CO3(aq)
Step 2: Separate the soluble ionic compounds into ions:
H2CO3(aq) → 2H+(aq) + CO32-(aq)
2NH3(aq) → 2NH4+(aq) + 2OH-(aq)
(NH4)2CO3(aq) → 2NH4+(aq) + CO32-(aq)
Step 3: Write the overall ionic equation by eliminating any spectator ions (ions that appear on both sides of the equation):
2H+(aq) + CO32-(aq) + 2NH4+(aq) + 2OH-(aq) → 2NH4+(aq) + CO32-(aq)
So, the ionic equation is:
H+(aq) + OH-(aq) → H2O(l)
To write the ionic equation, you first need to break down the given compounds into their respective ions. Here's how you can do that:
1. H2CO3 (aq) - Carbonic acid is a weak acid that dissociates into hydrogen ions (H+) and bicarbonate ions (HCO3-).
H2CO3 (aq) --> 2H+ (aq) + CO32- (aq)
2. 2NH3 (aq) - Ammonia is a weak base that produces ammonium ions (NH4+) and hydroxide ions (OH-) in water.
2NH3 (aq) --> 2NH4+ (aq) + 2OH- (aq)
3. (NH4)2CO3 (aq) - Ammonium carbonate dissociates into ammonium ions (NH4+) and carbonate ions (CO32-).
(NH4)2CO3 (aq) --> 2NH4+ (aq) + CO32- (aq)
Now, you can write the complete ionic equation by representing all the species that are present as ions:
2H+ (aq) + CO32- (aq) + 2NH4+ (aq) + 2OH- (aq) --> 2NH4+ (aq) + CO32- (aq)
Simplifying the equation by removing the spectator ions (ions that are present on both sides of the equation and do not participate in the reaction), you get the net ionic equation:
2H+ (aq) + 2OH- (aq) --> 2H2O (l)
Therefore, the ionic equation for the reaction is:
2H+ (aq) + 2OH- (aq) --> 2H2O (l)