Benson and Calvin won a total of 48 stickers in a game. Benson won 12 more stickers than Calvin. Express Calvin’s stickers as a fraction of Benson’s stickers.
b + c = 48
b = c + 12
so
c + 12 + c = 48
2 c = 36
etc
48 - 12 = 36 stickers
36/2 = 18 stickers
Calvin stickers = 18
Benson = 18 + 12 = 30 stickers
Express Calvin stickers |as a fraction of/means over| Benson stickers
Calvin stickers/Benson stickers = 18/30 = 3/5
To solve this problem, we need to find the number of stickers Benson and Calvin each have.
Let's assume that Calvin has x stickers.
According to the problem, Benson won 12 more stickers than Calvin. So, Benson would have x + 12 stickers.
The total number of stickers they won combined is 48. So, we can write the equation:
x + (x + 12) = 48
Simplifying this equation, we get:
2x + 12 = 48
Subtracting 12 from both sides, we get:
2x = 36
Dividing both sides by 2, we get:
x = 18
Therefore, Calvin has 18 stickers, and Benson has x + 12 = 18 + 12 = 30 stickers.
To express Calvin's stickers as a fraction of Benson's stickers, we divide the number of Calvin's stickers by the number of Benson's stickers:
Calvin's stickers / Benson's stickers = 18 / 30
Simplifying this fraction, we get:
Calvin's stickers / Benson's stickers = 3 / 5
So, Calvin's stickers can be expressed as the fraction 3/5 of Benson's stickers.