The 6th term of a gp is 2000.find the 23rd term if the common ratio is 10
The 6th term of a gp is 2000 ---> a(10)^5 = 2000
a = 2000/10^5 = 2*10^3/10^5 = 2/10^2
23rd term = ar^22
= 2/10^2 * 10^22
= 2*10^20
a = 2000/10^5 = 2*10^3/10^5 = 2/10^2
23rd term = ar^22
= 2/10^2 * 10^22
= 2*10^20