Maya school help an aluminum collection program in which they collected aluminum and brought it to be recycled . In the first week, Maya collected 4/20 lb of aluminum and her friend abigail collected 7/8 lb
A which girl collected more aluminum?
B How much aluminum did the two girl's collect?
It's worth 2 Points.
clearly, 4/20 < 7/8
since 4/10 is less than 1/2 and 7/8 is more than 1/2
4/20 + 7/8 = 8/40 + 35/40 = ____
Her friend :)
To compare the amount of aluminum collected by Maya and Abigail, we need to find a common denominator to make the fractions comparable. In this case, we can find the least common denominator (LCD) by calculating the least common multiple (LCM) of the denominators, which in this case is 40.
A) Comparing the amounts of aluminum collected:
Maya collected 4/20 lb of aluminum, which can be simplified to 1/5 lb.
Abigail collected 7/8 lb of aluminum.
To compare 1/5 lb and 7/8 lb, we need to find a common denominator of 40.
Converting 1/5 lb to 8ths:
1/5 lb = (1/5) * 8/8 = 8/40 lb
Now, comparing 8/40 lb and 7/8 lb:
8/40 lb vs 7/8 lb
Since 7/8 lb already has 8ths as the denominator, we can compare the numerators directly:
8 vs 7
Maya collected 8/40 lb of aluminum, and Abigail collected 7/8 lb of aluminum. Hence, Abigail collected more aluminum than Maya.
B) To find out how much aluminum Maya and Abigail collected in total, we need to add their individual amounts:
Maya collected 4/20 lb of aluminum, which we simplified to 1/5 lb earlier.
Abigail collected 7/8 lb of aluminum.
To add these two fractions, we need to find a common denominator of 40.
Converting 1/5 lb to 8ths:
1/5 lb = (1/5) * 8/8 = 8/40 lb
Now, adding the fractions:
8/40 lb + 7/8 lb
Since both fractions already have the same denominator (40 for the first fraction and 8 for the second fraction), we can add their numerators directly:
8 + 35 = 43
Therefore, Maya and Abigail collected a total of 43/40 lb of aluminum.