The 6th term of an A.P is twice the 3rd term. Find the number of term if the last term is 46 and the common difference is 2
d = 2
a+5d = 2(a+3d)
so,
a+10 = 3(a+6)
solve for a, then find n such that
a+2(n-1) = 46
a+5d = 2(a+3d)
so,
a+10 = 3(a+6)
solve for a, then find n such that
a+2(n-1) = 46