The disinfectant hydrogen peroxide (H2O2)
decomposes to form water and oxygen gas.
How much O2 will result from the decomposition of 5.94 mol of hydrogen peroxide?
2H2O2 ==> 2H2O + O2
5.94 mols H2O2 x (1 mol O2/2 mols H2O2) = 5.94 x 1/2 = ? mols O2
If you want grams that is g = mols x molar mass = ?
If you want volume @ STP that is volume = mols O2 x 22.4 L/mol = ?
To determine the amount of oxygen gas (O2) that will result from the decomposition of 5.94 moles of hydrogen peroxide (H2O2), we first need to construct a balanced equation for the decomposition reaction.
The balanced equation for the decomposition of hydrogen peroxide is as follows:
2 H2O2 → 2 H2O + O2
From the balanced equation, we can see that 2 moles of hydrogen peroxide will produce 1 mole of oxygen gas.
Therefore, to find the amount of oxygen gas produced from 5.94 moles of hydrogen peroxide, we can use the following proportion:
2 moles H2O2 : 1 mole O2 = 5.94 moles H2O2 : x moles O2
By cross-multiplying and solving for x, we can determine the amount of oxygen gas produced:
x = (1 mole O2 * 5.94 moles H2O2) / 2 moles H2O2
x = 2.97 moles O2
So, the decomposition of 5.94 moles of hydrogen peroxide will result in 2.97 moles of oxygen gas.
To determine how much oxygen gas (O2) is produced from the decomposition of 5.94 mol of hydrogen peroxide (H2O2), we need to use the balanced chemical equation.
The balanced chemical equation for the decomposition of hydrogen peroxide is:
2 H2O2 → 2 H2O + O2
From the balanced equation, we can see that for every 2 moles of hydrogen peroxide, 1 mole of oxygen gas is produced.
First, we need to calculate the number of moles of oxygen gas produced from 5.94 mol of hydrogen peroxide. To do this, we can use the mole ratio from the balanced equation.
Mole ratio: 2 moles of H2O2 = 1 mole of O2
Therefore, the number of moles of oxygen gas produced can be calculated as follows:
5.94 mol H2O2 × (1 mol O2 / 2 mol H2O2) = 2.97 mol O2
Therefore, 5.94 mol of hydrogen peroxide will produce 2.97 mol of oxygen gas.