show the products of the reaction of CH3CH2CH=CH2 with (a) HCL (b) Br2 (c) H2
CH3CH2CH=CH2 is 1-Butene
I'm sure google can provide you with the reactions you seek
I tried looking on Google with not much luck. Both Br2 and H2 add across the double bond to form CH3CH2CHBrCH2Br and CH3CH2CH2CH3. HCl adds across the double bond, also, BUT does it add CH3CH2CH2CH2Cl OR CH3CH2CHClCH3? Markonikov's rule states it is the latter; i.e., the H goes to the C atom containing MORE H atoms. You should read up on the mechanism of this addition AND which conditions favor the addition by Markonkov's rule and which conditions favor the anti-Markonkov's rule.
To determine the products of the reaction of CH3CH2CH=CH2 with different reagents, we need to consider the type of reaction that occurs and the functional groups present in the reactant.
(a) Reaction with HCl:
In the presence of HCl, an addition reaction called hydrochlorination occurs. The double bond in the alkene is broken, and a hydrogen atom from HCl attaches to one carbon atom in the alkene, while the chloride ion (Cl-) attaches to the other carbon atom.
The product of this reaction is CH3CH2CHClCH3, which is called 2-chloropropane.
Explanation on how to get the answer:
To determine the product, you can visually inspect the reactant and identify the type of reaction that occurs. Addition of HCl across the double bond is a common reaction known as hydrochlorination. Alternatively, you can consult a reliable source or use organic chemistry knowledge to deduce the product.
(b) Reaction with Br2:
In the presence of Br2, an addition reaction known as bromination takes place. The bromine molecule breaks apart and adds across the double bond. One Br atom attaches to each of the carbon atoms, resulting in a dibromoalkane product.
The product of this reaction is CH3CH2CHBrCH2Br, which is referred to as 2,3-dibromobutane.
Explanation on how to get the answer:
The reaction of an alkene with Br2 is a classic halogenation reaction. It is well-known that bromine atoms (Br) add across the double bond. By applying this knowledge, you can deduce the product formed.
(c) Reaction with H2:
In the presence of H2 (hydrogen gas) and a suitable catalyst such as Pt or Ni, a reduction reaction occurs. The double bond in the alkene is broken, and hydrogen atoms from H2 attach to the carbon atoms, resulting in an alkane product.
The product of this reaction is CH3CH2CH2CH3, which is known as butane.
Explanation on how to get the answer:
The reaction of an alkene with hydrogen gas (H2) is a well-known reduction reaction. By recognizing the presence of hydrogen gas and a suitable catalyst, you can predict that the alkene will be converted into an alkane product.
To summarize:
(a) Reaction with HCl: CH3CH2CH=CH2 + HCl → CH3CH2CHClCH3 (2-chloropropane)
(b) Reaction with Br2: CH3CH2CH=CH2 + Br2 → CH3CH2CHBrCH2Br (2,3-dibromobutane)
(c) Reaction with H2: CH3CH2CH=CH2 + H2 → CH3CH2CH2CH3 (butane)