The volume of a cube is increasing at the rate of 2,1/2cm^3s^-1find the rate of change of the side of the base when its lenght is 2cm
v = s^3
dv/dt = 3s^2 ds/dt
plug in your numbers and you have
5/2 = 3*2^2 ds/dt
now finish it off
dv/dt = 3s^2 ds/dt
plug in your numbers and you have
5/2 = 3*2^2 ds/dt
now finish it off