The rate of change of the radius of a sphere is constant. The rate of change of the volume is? TIA
v = 4/3 πr^3
dv/dt = 4πr^2 dr/dt
You can see that dv/dt is just the surface area times the change in radius.
Well, well, well, looks like we have ourselves a math question! If the rate of change of the radius of a sphere is constant, then we can use some fancy mathematics to figure out the rate of change of the volume.
First, let me pull out my math hat (it has a propeller on top, you know). The formula for the volume of a sphere is V = (4/3)πr^3, where V is the volume and r is the radius.
Now, to find the rate of change of the volume, we take the derivative with respect to time. This gives us dV/dt = 4πr^2(dr/dt), where dV/dt is the rate of change of the volume and dr/dt is the rate of change of the radius.
Since you mentioned that the rate of change of the radius is constant, let's give it a whimsical name, like "bob the magical rate of radius change." If bob is constant, then dr/dt becomes bob or just b. Therefore, we can simplify our equation to dV/dt = 4πr^2b.
So, my friend, the rate of change of the volume is 4πr^2b. It's as easy as that! Now you can go forth and impress your math friends with your newfound knowledge. Just remember to bring some clown jokes along with you for good measure!
To find the rate of change of the volume of a sphere when the rate of change of the radius is constant, we can use the formula for the volume of a sphere.
The volume of a sphere is given by the formula V = (4/3)πr^3, where V is the volume and r is the radius.
To find the rate of change of the volume with respect to the radius, we can take the derivative of the volume formula with respect to r.
dV/dr = 4πr^2
This derivative gives us the rate of change of the volume with respect to the radius. However, we are given that the rate of change of the radius is constant.
Let's assume the constant rate of change of the radius is represented by a constant k.
Therefore, dr/dt = k, where dt represents the change in time.
Now, we can calculate the rate of change of the volume.
To do this, we use the chain rule of differentiation, which states that the derivative of a composite function is equal to the derivative of the outer function multiplied by the derivative of the inner function.
Using the chain rule, we can express the rate of change of the volume of the sphere with respect to time as:
dV/dt = (dV/dr) * (dr/dt)
Substituting in the values we found earlier:
dV/dt = (4πr^2) * (k)
Simplifying further:
dV/dt = 4πk * r^2
So, the rate of change of the volume is given by 4πk times the square of the radius.
To find the rate of change of the volume of a sphere when the rate of change of the radius is constant, we need to use the chain rule from calculus.
Let's denote the radius of the sphere as "r" and the volume as "V". The relationship between the volume and radius of a sphere is given by the formula V = (4/3)πr³.
Now, if the rate of change of the radius (dr/dt) is constant, we can express it as a derivative dr/dt = k, where "k" is a constant.
To find the rate of change of the volume (dV/dt), we need to differentiate the volume formula with respect to time (t) using the chain rule.
dV/dt = dV/dr * dr/dt
Taking the derivative of the volume formula, we get:
dV/dr = d/dt [(4/3)πr³]
= 4πr² * (dr/dr) (Applying the power rule of differentiation)
= 4πr²
Now, substituting dr/dt = k (since it is given that the rate of change of the radius is constant), we have:
dV/dt = (4πr²) * k
Therefore, the rate of change of the volume of a sphere when the rate of change of the radius is constant is (4πr²) * k.