Calculate the concentration of sodium trioxonitrate iv in mole per dm3
The molarity of a pure liquid or a pure solid makes no sense BECAUSE molarity = mols/dm^3 of solution and there is no solution here; i.e., there is no solvent. Most questions of this sort mean the density/molar mass.
So look up the density of NaNO3 (Google will do that for you) and divide by the molar mass (85 g/mol).
To calculate the concentration of sodium trioxonitrate IV (also known as sodium nitrate, NaNO3) in mole per dm^3, you need to know the number of moles of NaNO3 and the volume of the solution in dm^3.
Here's how you can calculate it:
1. Determine the number of moles of NaNO3.
- This can be done by dividing the mass of NaNO3 by its molar mass (58.44 g/mol).
- If you have the mass of NaNO3 in grams, divide that by the molar mass to get the number of moles.
2. Measure the volume of the solution in dm^3.
- Use a graduated cylinder or any other appropriate measuring device to measure the volume of the solution directly in dm^3 (cubic decimeters).
3. Calculate the concentration.
- Divide the number of moles of NaNO3 by the volume of the solution in dm^3.
- The resulting value will be the concentration of NaNO3 in mole per dm^3.
For example, let's say you have 2.5 grams of NaNO3 dissolved in 500 ml (0.5 dm^3) of solution:
1. Determine the number of moles of NaNO3.
- The molar mass of NaNO3 is 58.44 g/mol.
- Number of moles = 2.5 g / 58.44 g/mol ≈ 0.043 mol.
2. Measure the volume of the solution in dm^3.
- 500 ml = 0.5 dm^3.
3. Calculate the concentration.
- Concentration = 0.043 mol / 0.5 dm^3 ≈ 0.086 mol/dm^3.
Therefore, the concentration of sodium trioxonitrate IV in this solution is approximately 0.086 mol/dm^3.