Jeff has a total of 22 chickens and pigs altogether. When he counted the total amount of legs the farm animals has, he got the answer of 78. How many pigs are there? How many chickens are there?
if there are p pigs, then the rest (22-p) are chickens. So, counting the legs,
4p + 2(22-p) = 78
Thank you!
To find the number of pigs and chickens, let's set up a system of equations based on the given information.
Let's assume that the number of pigs is represented by "P", and the number of chickens is represented by "C."
From the given information, we can set up two equations:
Equation 1: P + C = 22 (since Jeff has a total of 22 chickens and pigs together)
Equation 2: 4P + 2C = 78 (since each pig has 4 legs and each chicken has 2 legs)
To solve these equations, we can use a method called substitution or elimination.
Let's use substitution in this case:
From Equation 1, we can rewrite it as P = 22 - C.
Substituting this value of P into Equation 2, we get 4(22 - C) + 2C = 78.
Let's simplify this equation:
88 - 4C + 2C = 78
Combining like terms, we get:
-2C = 78 - 88
-2C = -10
Dividing both sides by -2, we get:
C = 5
Now, substitute this value of C back into Equation 1 to find the value of P:
P + 5 = 22
P = 22 - 5
P = 17
Therefore, there are 17 pigs and 5 chickens on Jeff's farm.