what is the greatest whole number with all digits different, and the product is 24
8*3 = 2*2*2*3
83 ? nah
try
3222
Nah, digits have to be different
so
maybe
432
831
To find the greatest whole number with all digits different, such that the product of its digits is 24, we can use a systematic approach.
Let's start by listing the factors of 24: 1, 2, 3, 4, 6, 8, and 12.
Now, consider the units digit of the number. It should be a factor of 24. Since we need the greatest whole number, the units digit should be the largest possible factor, which is 8.
Next, we need to choose the tens digit. It should be a factor of 24 as well but different from the units digit. The factors of 24 that are left are 1, 2, 3, 4, 6, and 12. Among these options, the greatest is 6, so we choose 6 as the tens digit.
Finally, choose the hundreds digit, which should be a factor of 24 and different from both the units and tens digits. Among the remaining options, 1, 2, 3, and 4, the greatest factor is 4, so we choose 4 as the hundreds digit.
Therefore, the greatest whole number with all different digits, and a product of digits equal to 24, is 486.