. Peter is heating water on the stove to boil eggs for a picnic. How much heat is required to raise the
Temperature of his 10.0kg vat of water from 20.00 C to 100.00 C?
q = mass H2O x specific heat H2O x Tfinal - Tinitial)
I would use 10,000 for mass H2O in grams. You will need to look up specific heat H2O. Tfinal and Tintial are in the problem.
To calculate the amount of heat required to raise the temperature of the water, you need to use the formula:
Q = mcΔT
Where:
Q = Heat energy (in joules)
m = Mass of the water (in kg)
c = Specific heat capacity of water (4.184 J/g°C or 4184 J/kg°C)
ΔT = Change in temperature (in °C)
First, convert the mass of water from kg to grams:
m = 10.0 kg * 1000 g/kg
m = 10,000 g
Now we can plug the values into the formula:
Q = (10,000 g) * (4184 J/kg°C) * (100.00°C - 20.00°C)
Calculating the difference in temperature:
ΔT = 100.00°C - 20.00°C
ΔT = 80.00°C
Q = (10,000 g) * (4184 J/kg°C) * (80.00°C)
Now calculate the heat required:
Q = 33,472,000 J
So, it would require 33,472,000 joules of heat to raise the temperature of the 10.0 kg vat of water from 20.00°C to 100.00°C.
To calculate the amount of heat required to raise the temperature of water, you need to use the specific heat capacity of water and the formula:
Q = m * c * ΔT
Where:
Q is the amount of heat (energy) required,
m is the mass of the water,
c is the specific heat capacity of water,
ΔT is the change in temperature.
In this case, the mass of the water is given as 10.0 kg, the initial temperature is 20.00 degrees Celsius, and the final temperature is 100.00 degrees Celsius.
The specific heat capacity of water is approximately 4.18 J/g•°C. Since we have the mass of water in kg, we need to convert the specific heat capacity to J/kg•°C.
1 g = 0.001 kg
So, 4.18 J/g•°C = 4.18 J/ (0.001 kg•°C) = 4180 J/kg•°C
Now we can plug in the values into the formula.
Q = (10.0 kg) * (4180 J/kg•°C) * (100.00 °C - 20.00 °C)
Q = 10.0 kg * 4180 J/kg•°C * 80.00 °C
Q ≈ 3,344,000 J
Therefore, approximately 3,344,000 joules of heat are required to raise the temperature of the 10.0 kg vat of water from 20.00 °C to 100.00 °C.