What volume of hydrogen gas at STP is produced by the complete reaction of 15.0 g of sodium according to the following equation:
2Na + 2H2O -----> 2NaOH + H2?
I'll help with the others after you have done your thing.
ibj
To find the volume of hydrogen gas produced, we can use the concept of stoichiometry.
1. Start by finding the number of moles of sodium (Na) in 15.0 g using the molar mass of sodium:
molar mass of Na = 22.99 g/mol
moles of Na = mass of Na / molar mass of Na
= 15.0 g / 22.99 g/mol
2. The balanced chemical equation states that 2 moles of sodium react to produce 1 mole of hydrogen gas (H2). So, the number of moles of H2 produced will be half the number of moles of Na.
3. Now, we need to convert moles of H2 to volume at STP (Standard Temperature and Pressure). One mole of any gas at STP occupies 22.4 liters.
volume of H2 gas (at STP) = moles of H2 * 22.4 L/mol
4. Substitute the values into the equation to calculate the volume of hydrogen gas:
volume of H2 gas (at STP) = (moles of Na / 2) * 22.4 L/mol
Plug in the value of moles of Na into the equation and complete the calculation to find the final result.