1.577 moles of a solution of AgNo3 has a density of 1.220 g/ml what is the molarity of this solution
To find the molarity of a solution, we need to know the number of moles of the solute (AgNO3) and the volume of the solution. From the given information, we have the following:
Number of moles of AgNO3 = 1.577 mol
Density of the solution = 1.220 g/mL
To determine the volume of the solution, we can use the formula:
Volume (V) = Mass (m) / Density (d)
Since we are given the density and need to find the volume, we rearrange the formula as:
V = Mass / Density
However, since we do not have the mass directly, we can calculate it using the following relationship:
Mass (m) = Number of moles (n) × Molar mass (M)
To find the molar mass of AgNO3, we need to add up the atomic masses of the individual elements: Ag (silver), N (nitrogen), and O (oxygen).
The atomic mass of Ag is approximately 107.87 g/mol, N is 14.01 g/mol, and O is 16.00 g/mol.
Molar mass (M) of AgNO3 = (Ag: 1 × atomic mass of Ag) + (N: 1 × atomic mass of N) + (O: 3 × atomic mass of O)
M = (1 × 107.87) + (1 × 14.01) + (3 × 16.00)
Now, we can substitute the values into the equations and solve for the volume:
Mass (m) = Number of moles (n) × Molar mass (M)
Mass = 1.577 mol × [(1 × 107.87) + (1 × 14.01) + (3 × 16.00)]
Once we calculate the mass, we can plug it into the volume equation:
Volume (V) = Mass / Density
Finally, we can calculate the molarity (M) using the formula:
Molarity (M) = Number of moles (n) / Volume (V)
By following these steps, you can find the molarity of the given solution.