1.577 moles of AgNO3 has density of 1.220 g/mol. what is it's molarity?
To find the molarity of a solution, you need to know the number of moles of solute and the volume of the solution in liters.
Given:
Number of moles of AgNO3 = 1.577 moles
Density of AgNO3 = 1.220 g/mol
First, we need to calculate the mass of AgNO3 using the density and number of moles:
Mass = Number of moles * molar mass
Molar mass (AgNO3) = 107.87 g/mol + 14.01 g/mol + (3 * 16.00 g/mol) = 169.87 g/mol
Mass = 1.577 moles * 169.87 g/mol = 267.836 g
Now, to find the volume (V) of the solution, we need to use the formula:
Density = Mass / Volume
Rearranging the formula:
Volume = Mass / Density
Volume = 267.836 g / (1.220 g/mol) = 219.465 mol
Finally, we can calculate the molarity (M) using the formula:
Molarity = Number of moles / Volume
Molarity = 1.577 moles / 0.219465 L = 7.18 M
So, the molarity of the solution is 7.18 M (mol/L).