A sample of ammonium nitride ((NH4)3N) has a mass of 3.22 g.
(a) How many NH4+ ions are present?
ions
(b) How many N3- ions are present?
ions
(c) What is the mass in grams of one formula unit of (NH4)3N?
What mass of CO2 could be produced from 14.8 g of C2H5OH? Assume C2H5OH is the limiting reactant.
What mass of O2 would be consumed?
What mass of H2O would be produced?
mass ammonium nitride ((NH4)3N) = 3.22 g.
mols [(NH4)3N] = 3.22/68 = 0.0474
NH4^+ ions = 3 x 0.0474
N^- = 1 x 0.0474
68 frm above.
To determine the number of ions and the mass of one formula unit in (NH4)3N, we first need to understand the chemical formula and the molar mass of each component.
(a) Number of NH4+ ions:
In the ammonium nitride formula, (NH4)3N, there are three ammonium ions, NH4+. Each ammonium ion consists of one nitrogen atom and four hydrogen atoms.
Mass of NH4+ = Mass of 1 nitrogen atom + Mass of 4 hydrogen atoms
To find the mass of NH4+:
- Look up the atomic masses of nitrogen (N) and hydrogen (H) from the periodic table.
- Multiply the atomic mass of nitrogen by 1 and the atomic mass of hydrogen by 4.
- Add these values together to find the mass of NH4+.
(b) Number of N3- ions:
In the formula (NH4)3N, there is one nitride ion, N3-. Each nitride ion consists of one nitrogen atom.
Mass of N3- = Mass of 1 nitrogen atom
To find the mass of N3-:
- Look up the atomic mass of nitrogen from the periodic table.
(c) Mass of one formula unit:
A formula unit in (NH4)3N includes three ammonium ions and one nitride ion.
To find the mass of one formula unit:
- Multiply the mass of NH4+ by 3 (to include three ammonium ions).
- Add the mass of N3- to this value.
Now, let's calculate the values:
(a) Number of NH4+ ions:
1. Look up the atomic masses:
- Nitrogen (N): 14.01 g/mol
- Hydrogen (H): 1.01 g/mol
2. Calculate the mass of NH4+:
- Mass of NH4+ = (1 × Mass of N) + (4 × Mass of H)
= (1 × 14.01 g/mol) + (4 × 1.01 g/mol)
= 14.01 g/mol + 4.04 g/mol
= 18.05 g/mol
3. Calculate the number of NH4+ ions:
- Number of NH4+ ions = Mass of (NH4)3N / Mass of NH4+
= 3.22 g / 18.05 g/mol
(b) Number of N3- ions:
1. Look up the atomic mass:
- Nitrogen (N): 14.01 g/mol
2. Calculate the number of N3- ions:
- Since the formula (NH4)3N has one N3- ion, the number of N3- ions is 1.
(c) Mass of one formula unit:
1. Calculate the mass of one formula unit:
- Mass of one formula unit = (3 × Mass of NH4+) + Mass of N3-
= (3 × 18.05 g/mol) + 14.01 g/mol
By following these steps and performing the calculations, you should be able to determine the number of ions and the mass of one formula unit in (NH4)3N.