your drawer contains 11 red socks and 6 blue socks. its too dark to see which is which, but you need a pair of socks so you grab two. What is the probability that both socks will are red?
prob(red, red) = (11/17)(10/16) = 55/136
or
C(11,2) / C(17,2) = 55/136
plz i need your help ive been stressing out for the past 2 hours!! :(((
To determine the probability of grabbing two red socks, you need to calculate the probability of selecting one red sock on the first try, and then multiply that by the probability of selecting another red sock on the second try.
Let's break it down step by step:
Step 1: Calculate the probability of selecting a red sock on the first try.
You have a total of 11 red socks and 17 socks in total (11 red + 6 blue). So the probability of selecting a red sock on the first try is 11/17.
Step 2: Calculate the probability of selecting a red sock on the second try.
Since you didn't replace the first sock, there will be one less sock in the drawer for the second pick. There will now be 10 red socks left and a total of 16 socks in the drawer. Thus, the probability of selecting a second red sock is 10/16.
Step 3: Multiply the probabilities from Step 1 and Step 2.
To find the probability of both events occurring (selecting a red sock on the first try and a red sock on the second try), you need to multiply the probabilities together.
(11/17) * (10/16) = 110/272 ≈ 0.4044
So, the probability of selecting two red socks is approximately 0.4044 or 40.44%.