Aqueous solutions of copper(I) chloride and hydrosulfuric acid (H2S) react to form copper(I) sulfide and hydrochloric acid.
a. Write a balance chemical equation for this reaction; include states of matter.
b. A reaction with a theoretical yield of 14.2 moles of copper(I) sulfide is carried out, but only 12.5 moles are produced. What is the percent yield of copper(I) sulfide?
c. What mass (g) of copper(I) sulfide was produced?
d. What theoretical mass (g) of copper(I) sulfide could have been produced?
a. Write a balance chemical equation for this reaction; include states of matter.
CuCl + 2H2S ==> Cu2S + 2HCl
b. A reaction with a theoretical yield of 14.2 moles of copper(I) sulfide is carried out, but only 12.5 moles are produced. What is the percent yield of copper(I) sulfide?
%yield = (actual yield/theoretical yield)*100 = ?
c. What mass (g) of copper(I) sulfide was produced?
mass Cu2S = mols Cu2S produced x molar mass Cu2S = ?
d. What theoretical mass (g) of copper(I) sulfide could have been produced?
theoretical mass Cu2S =theoretical mole Cu2S x molar mass Cu2S = ?
Post your work if you get stuck.
Thank you
To answer these questions, we need to first write the balanced chemical equation for the reaction. This equation provides the stoichiometric relationship between the reactants and products in the reaction.
a. The balanced chemical equation for the reaction is:
2CuCl(aq) + H2S(aq) → Cu2S(s) + 2HCl(aq)
In this equation, (aq) represents an aqueous solution, (s) represents a solid precipitate, and the coefficients represent the stoichiometric ratios between the reactants and products.
Now let's move on to the other questions.
b. To find the percent yield of copper(I) sulfide, we need to compare the actual yield of 12.5 moles with the theoretical yield of 14.2 moles. The percent yield can be calculated using the formula:
Percent Yield = (Actual Yield / Theoretical Yield) * 100
Substituting the given values:
Percent Yield = (12.5 moles / 14.2 moles) * 100
c. To calculate the mass of copper(I) sulfide produced, we need to know the molar mass of Cu2S. Copper(I) sulfide (Cu2S) has a molar mass of 159.16 g/mol. The mass can be calculated using the formula:
Mass = Number of moles * Molar Mass
Substituting the given values:
Mass = 12.5 moles * 159.16 g/mol
d. To find the theoretical mass of copper(I) sulfide that could have been produced, we use the same formula as in part (c), but this time using the theoretical yield of 14.2 moles:
Theoretical Mass = Theoretical Yield * Molar Mass
Substituting the given values:
Theoretical Mass = 14.2 moles * 159.16 g/mol
By following these steps and using the given information, you can find the balance chemical equation, calculate the percent yield, and determine the mass of copper(I) sulfide produced as well as the theoretical mass that could have been produced.