In dilute nitric acid, HNO3, copper metal dissolves according to the following equation:
3Cu(s) + 8HNO3(aq) ----> 3Cu(NO3)2(aq) + 2NO(g) + 4H2O(aq)
How many Liters of NO are formed from 5.78 x 1024 molecules of HNO3
plug means to substitute while chug means to solve the equation after substitution. Plug 'n chug is an easy way of saying you have the formula and the numbers, go get it (the answer).
how many moles of HNO3 do you have?
You will get 1/4 that many moles of NO
At STP, 1 mole occupies 22.4L
So plug and chug
what does plug and chug mean :/
ok thank you!
To determine the number of liters of NO formed from a given number of HNO3 molecules, you need to use the balanced chemical equation and the concept of stoichiometry.
The balanced chemical equation tells us the ratio of reactants and products in the chemical reaction. In this case, for every 8 molecules of HNO3, 2 molecules of NO are produced.
1. Start with the given number of HNO3 molecules: 5.78 x 10^24 molecules.
2. Convert the number of HNO3 molecules to moles. Since 1 mole contains Avogadro's number of particles (6.022 x 10^23), divide the given number of molecules by Avogadro's number:
5.78 x 10^24 molecules / 6.022 x 10^23 molecules/mol = 9.6 moles of HNO3.
3. Use the stoichiometric ratio from the balanced equation to find the number of moles of NO produced. From the balanced equation, the ratio of HNO3 to NO is 8:2. Therefore, for every 8 moles of HNO3, 2 moles of NO are produced.
9.6 moles HNO3 x (2 moles NO / 8 moles HNO3) = 2.4 moles NO.
4. Convert the moles of NO to liters. Since the volume of a gas depends on temperature, pressure, and the number of moles, you need to use the ideal gas law. Assuming standard temperature and pressure (STP), which is 0 °C (273 K) and 1 atmosphere (atm) respectively, you can use the following conversion factor:
1 mole of any ideal gas at STP = 22.4 liters.
Therefore, the number of liters of NO is:
2.4 moles NO x (22.4 liters NO / 1 mole NO) = 53.76 liters NO.
So, from 5.78 x 10^24 molecules of HNO3, approximately 53.76 liters of NO are formed.