at 90 degrees C, 60g of KCl is dissolved in 100g of water. is this solution saturated, unsaturated or supersaturated
I don't have the slightest idea of the solubility of KCl. Don't you have a graph or a table listing that? I found this on the web.
https://www.gusd.net/cms/lib/CA01000648/Centricity/Domain/1822/Act.%2014.3%20Solubility%20Curves.pdf
To determine whether the solution is saturated, unsaturated, or supersaturated, we need to compare the amount of solute (KCl) that is dissolved at a given temperature (90°C) to the maximum amount of solute that can be dissolved at that temperature.
To find the maximum amount of solute that can be dissolved, we can use solubility data. Solubility refers to the maximum amount of solute that can be dissolved in a given amount of solvent (in this case, water) at a specific temperature.
Let's assume that at 90°C, the solubility of KCl in water is 70g/100g. This means that at 90°C, 100g of water can dissolve up to 70g of KCl.
However, in the given problem, only 60g of KCl is dissolved in 100g of water at 90°C. Since this amount of solute is less than the maximum solubility at that temperature, the solution is unsaturated.
Therefore, the solution is unsaturated as it contains less solute (KCl) than the maximum amount that can be dissolved at 90°C.