I have been stuck on this question for two days cans someone please help.
s = ∫ √(1 + x'^2) dy so that would be ∫[1,5]√(1 + (3/2 √(y-1))^2) dy = ∫[1,5]√(1 + 9/4 (y-1)) dy = 1/2 ∫[1,5]√(9y-5) dy = 8/27 (10√10 - 1)
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