Mario rolls a 6-sided die 60 times. About how many times should he expect it to land on an 2?
Probability of landing on 2 is 1/6. Multiply that by 60.
The probability of one roll for each of the 6 possible numbers, including number 2, is 1 / 6
After 1 roll probability = 1 / 6
After 2 rolls probability = 2 ∙ 1 / 6
After 3 rolls probability = 3 ∙ 1 / 6
etc.
After 60 rolls probability = 60 ∙ 1 / 6 = 60 / 6 = 10
To find out how many times Mario should expect the die to land on a 2 when rolling it 60 times, we can use the concept of probability. The die has 6 sides, so the probability of rolling a 2 on any given roll is 1/6 or approximately 0.1667.
To calculate the expected number of times, we can multiply the probability of rolling a 2 on any given roll by the total number of rolls.
Expected Number of 2s = Probability of Rolling 2 × Total Number of Rolls
Expected Number of 2s = 0.1667 × 60
Expected Number of 2s = 10
Therefore, Mario should expect the die to land on a 2 approximately 10 times when rolling it 60 times.