what is the factor form of this polynomial 3X^3 - 3x^2 - 36x?

3x^3 - 3x^2 - 36x , first I see a common factor of 3x

= 3x(x^2 - x - 12) , now a nice quadratic which you can factor in your head
=3x(x - 4)(x + 3)

sry if its wrong mate

just do it

Thanks mathhelper that is so right :)

To find the factor form of a polynomial, we need to factor out the common factors from each term.

In this case, we can factor out an "3x" from each term:
3x(x^2 - x - 12)

Now, we need to factor the quadratic polynomial inside the parentheses: x^2 - x - 12.

To factor this quadratic polynomial, we need to find two numbers whose product is -12 and whose sum is -1 (since the coefficient of the middle term is -1).

The numbers that satisfy these conditions are -4 and 3.

Therefore, we can rewrite the quadratic polynomial as:
x^2 - x - 12 = (x - 4)(x + 3)

Putting it all together, the factor form of the polynomial 3x^3 - 3x^2 - 36x is:
3x(x - 4)(x + 3)

2-3 . - 6x + 9 , If the factor 2 be suppressed , in the second polynomial , as the rule ... A factor of that form may be suppressed , in this example , and set aside , as a part ... 2 ) 2x4—12x3 + 1922 4x18.2 + 19x - 3 ) 24 6x3 + 9.22 - 3x + 4.1 16 = 42 ... + 76x2— 36x + 72 - 24x3 + 108.x2–114x + 18 2 ) — 32x2 + 78x + 54 , 1st Rem .

IM SORRY I CANT ATLEAST TRY ANY THING