How would you make 500mL of 1.5M HCL from a stock solution of 12.0 M HCL?
I would use the dilution formula of
mL1 x M1 = mL2 x M2
500 mL x 1.5M = mL2 x 12.0M
Solve for mL2, pipet that volume of the 12.0 M stuff into a 500 mL volumetric flask. add some distilled water (perhaps 300 mL or so), swirl, add distilled H2O to the mark on the volumetric flask. stopper, mix thoroughly, label. done.
To make 500mL of a 1.5M HCl solution from a stock solution of 12.0M HCl, you can follow these steps:
1. Use the formula: M1V1 = M2V2, where M1 is the initial concentration, V1 is the initial volume, M2 is the final concentration, and V2 is the final volume.
2. Plug in the given values:
M1 (initial concentration) = 12.0M
V1 (initial volume) = ?
M2 (final concentration) = 1.5M
V2 (final volume) = 500mL or 0.5L
3. Rearrange the formula to solve for V1:
V1 = (M2 * V2) / M1
4. Substitute the values:
V1 = (1.5M * 0.5L) / 12.0M
5. Calculate:
V1 = 0.0625L or 62.5mL
Therefore, to make 500mL of a 1.5M HCl solution from a stock solution of 12.0M HCl, you will need to measure 62.5mL of the 12.0M HCl stock solution and add it to a container. Then, add distilled water or the appropriate solvent to make a total volume of 500mL.
To make 500 mL of a 1.5 M HCl solution from a 12.0 M HCl stock solution, you need to perform a dilution calculation.
Here's the step-by-step process:
1. Determine the desired final volume of the solution, which is 500 mL.
2. Calculate the volume of the stock solution needed using the dilution formula:
C1V1 = C2V2
where:
C1 = concentration of the stock solution (12.0 M)
V1 = volume of the stock solution needed
C2 = desired concentration (1.5 M)
V2 = desired final volume (500 mL)
Plugging in the known values, we get:
(12.0 M)(V1) = (1.5 M)(500 mL)
3. Solve the equation for V1:
V1 = (1.5 M)(500 mL) / (12.0 M)
V1 ≈ 62.5 mL
Therefore, you would measure 62.5 mL of the 12.0 M HCl stock solution and then add enough solvent (usually water) to reach a final volume of 500 mL to obtain a 1.5 M HCl solution.