A powerful motorcycle can accelerate from rest to 27.1 m/s in only 4.37 s.
1)What is its average acceleration?
__________________________m/s^2
2) How far does it travel in that time?
__________________________m
acceleration = change in velocity / change in time
if a is constant then v is linear in time and
average speed = (final speed + original speed ) / 2
= ( 27.1+ 0 ) / 2
distance = average speed * time
@Anonymous Thank you! I got it!
1)What is its average acceleration?
6.20137299771 m/s^2
2) How far does it travel in that time?
59.2135 m
To find the average acceleration of the motorcycle, we need to use the formula:
Average acceleration (a_average) = Change in velocity (Δv) / Time taken (Δt)
Given:
Initial velocity (u) = 0 m/s (since it starts from rest)
Final velocity (v) = 27.1 m/s
Time taken (Δt) = 4.37 s
Step 1: Calculate the change in velocity (Δv)
Δv = v - u
Δv = 27.1 m/s - 0 m/s
Δv = 27.1 m/s
Step 2: Calculate the average acceleration (a_average)
a_average = Δv / Δt
a_average = 27.1 m/s / 4.37 s
Therefore, the average acceleration of the motorcycle is 6.198 m/s^2 (rounded to three decimal places).
To find the distance traveled by the motorcycle, we need to use the equation:
Distance (d) = Initial velocity (u) * Time (t) + (1/2) * Average acceleration (a_average) * Time (t)^2
Given:
Initial velocity (u) = 0 m/s (since it starts from rest)
Time (t) = 4.37 s
Average acceleration (a_average) = 6.198 m/s^2
Step 1: Calculate the distance traveled by the motorcycle
d = 0 m/s * 4.37 s + (1/2) * 6.198 m/s^2 * (4.37 s)^2
Therefore, the motorcycle travels a distance of 53.6 meters (rounded to two decimal places) in that time.