Calculate the molar concentration of HNO, (63.0 g/mol) in a solution that has a specific gravity of 1.42 and is 70.5% HNO, (w/w).

The 3 must be missing from your keyboard. That's HNO3 for nitric acid.

1.42 g/mL x 1000 mL x 0.705 x (1/63) = ? molarity.
To break this down goes this way.
1.42 g/mL x 1000 mL = mass of H2O and HNO3 in 1000 mL of solution.
That x 0.705 = mass of the HNO3. The rest of it is H2O
(1/63) convert mass HNO3 to mols HNO3.
That is in 1 L solution and mols/L is molarity.

Describe the preparation of 100 HL of 6.0 M HCL from a concentrated solu-tion that has a specific gravity of 1.18 and is 37% (w/w) HCl (36.5 g/mol).

See above.

تحليلية

A 2 g of CrCl3 (158g/mol) and a 2 g of CaCl2 (111g/mol) was dissolved and treated with excess AgNO3 (170 g/mol), calculate the mass of AgCl (143g/mol) precipitate formed

To calculate the molar concentration of HNO3 in the solution, we need to follow a few steps:

Step 1: Calculate the mass of HNO3 in the solution.
Given that the solution has a specific gravity of 1.42 and is 70.5% HNO3 (w/w), we can assume we have 100 grams of the solution. Therefore, the mass of HNO3 in the solution is calculated by multiplying the mass of the solution (100 g) by the percent composition of HNO3 (70.5%):

Mass of HNO3 = Mass of solution × Percent composition of HNO3
Mass of HNO3 = 100 g × 0.705
Mass of HNO3 = 70.5 g

Step 2: Calculate the number of moles of HNO3 using its molar mass.
The molar mass of HNO3 is given as 63.0 g/mol. To calculate the number of moles, we divide the mass of HNO3 by its molar mass:

Number of moles of HNO3 = Mass of HNO3 / Molar mass
Number of moles of HNO3 = 70.5 g / 63.0 g/mol
Number of moles of HNO3 = 1.12 mol

Step 3: Calculate the molar concentration of HNO3.
The concentration is usually measured in moles per liter (mol/L). However, in this case, we need to convert grams of solution to liters using the specific gravity.

Mass of solution = Mass of HNO3 / Percent composition of HNO3
Mass of solution = 70.5 g / 0.705
Mass of solution = 100 g

Volume of solution = Mass of solution / Density
Volume of solution = 100 g / 1.42 g/mL
Volume of solution = 70.4 mL

Converting mL to L:
Volume of solution = 70.4 mL × (1 L / 1000 mL)
Volume of solution = 0.0704 L

Finally, to calculate the molar concentration (C):

C = Number of moles of HNO3 / Volume of solution
C = 1.12 mol / 0.0704 L
C ≈ 15.91 mol/L

Therefore, the molar concentration of HNO3 in the solution is approximately 15.91 mol/L.