2H2 + O2 = 2H2O
how many moles of water are produced from 128g of O2
2H2 + O2 = 2H2O
mols O2 = grams/molar mass = 128/32 = ?
Look at the coefficients in the balanced equation. You get 2 mols H2O for every 1 mol O2
To find the number of moles of water produced from 128g of O2, we need to use the given balanced chemical equation for the reaction: 2H2 + O2 = 2H2O.
1. Start by finding the molar mass of O2 (oxygen gas). Oxygen has an atomic mass of approximately 16g/mol, and since O2 consists of 2 oxygen atoms, its molar mass is 16g/mol * 2 = 32g/mol.
2. Next, calculate the number of moles of O2 in 128g by using the formula: Moles = Mass / Molar Mass. Thus, Moles of O2 = 128g / 32g/mol = 4 mol.
3. According to the balanced equation, 1 mole of O2 produces 2 moles of H2O. So, if we have 4 moles of O2, we can expect that 4 moles of O2 would produce 4 mol O2 * (2 mol H2O / 1 mol O2) = 8 moles of H2O.
Therefore, from 128g of O2, 8 moles of water (H2O) will be produced.