What are the odds of reaching into the bag and grabbing a white marble then without replacement reaching in and grabbing another white marble.
There are 2 black marbles, 4 white marbles, and 4 striped marbles in the bag
I NEED HELP!
10 marbles in all, so
4/10 * 3/9 = ____
To find the odds of grabbing a white marble and then, without replacement, grabbing another white marble from the bag, we need to calculate the probability of each event.
First, let's find the probability of grabbing a white marble on the first draw. Since there are a total of 2 black marbles, 4 white marbles, and 4 striped marbles, the probability of grabbing a white marble on the first draw is 4/10 (4 white marbles out of a total of 10 marbles).
Next, we calculate the probability of grabbing a white marble on the second draw, without replacement. After selecting one white marble, there will be 3 white marbles left in the bag, along with the remaining 9 marbles. Thus, the probability of selecting another white marble is 3/9.
To calculate the overall probability, we multiply the probabilities of each event. So the odds of grabbing a white marble and then, without replacement, grabbing another white marble are (4/10) * (3/9) = 2/15.
Therefore, the odds of reaching into the bag and grabbing a white marble, and then grabbing another white marble without replacement, are 2/15.