Calculate %composition of element in the following compounds-Na2Co3.10H2O
Done just like % composition of anything; i.e., (mass of the desired constituent/mass whole thing)* 100 = ?
%Na = (2*atomic mass Na)/molar mass Na2CO3,10H2O
% C = atomic mass C/molar mass Na2CO3.10H2O
Etc
Post your work if you get stuck.
To calculate the percentage composition of an element in a compound, you need to know the molar mass of the compound and the molar mass of the element.
To find the molar mass of Na2CO3·10H2O (sodium carbonate decahydrate), you need to add up the molar masses of each element in the compound. The molar masses is given as follows:
Na: 22.99 g/mol
C: 12.01 g/mol
O: 16.00 g/mol
H: 1.01 g/mol
The molar mass of Na2CO3·10H2O is:
2(22.99 g/mol) + 12.01 g/mol + 3(16.00 g/mol) + 10(2(1.01 g/mol) + 16.00 g/mol) = 286.18 g/mol
Now, let's calculate the percentage composition of the element in the compound.
Percentage composition = (Molar mass of the element / Molar mass of the compound) * 100
For example, let's calculate the percentage composition of Na (sodium) in Na2CO3·10H2O:
Percentage composition of Na = (2(22.99 g/mol) / 286.18 g/mol) * 100 = 16.03%
Similarly, you can calculate the percentage composition of other elements (C, O, and H) in Na2CO3·10H2O by using their respective molar masses.
To calculate the percent composition of an element in a compound, you need to know the molar mass of the element and the molar mass of the compound.
First, let's find the molar mass of the compound Na2CO3.10H2O:
Molar mass of Na = 22.99 g/mol
Molar mass of C = 12.01 g/mol
Molar mass of O = 16.00 g/mol
Molar mass of H = 1.01 g/mol
For Na2CO3, multiply the molar mass of Na by 2, add the molar mass of C and multiply by 1, and add the molar mass of O and multiply by 3:
Molar mass of Na2CO3 = 2(22.99) + 12.01 + 3(16.00) = 105.99 g/mol
For 10H2O, multiply the molar mass of H by 2 and the molar mass of O by 10:
Molar mass of 10H2O = 10(1.01) + 10(16.00) = 180.10 g/mol
Now, let's find the percent composition of Na in Na2CO3.10H2O:
Percent Na = (2 * (molar mass of Na) / molar mass of Na2CO3.10H2O) * 100
Percent Na = (2 * 22.99 / (105.99 + 180.10)) * 100
Percent Na = (45.98 / 286.09) * 100
Percent Na = 0.1607 * 100
Percent Na = 16.07%
Therefore, the percent composition of Na in Na2CO3.10H2O is 16.07%.