What is the 15th term of the linear sequence below?
22,18,14,10,6
a1 = 22 , d = - 4
an = a1 + ( n - 1 ) d
n = 15
a15 = 22 + ( 15 - 1 ) ∙ ( - 4 )
a15 = 22 + 14 ∙ ( - 4 )
a15 = 22 - 56
a15 = - 34
a1 = 22
d = -4
a15 = a+14d = ____
thank you
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THE ANSWER IS -34 (I got the question wright with that answer)
Yes, that is correct. The 15th term of the given linear sequence is -34.
To find the 15th term of a linear sequence, we need to first determine the pattern or rule followed by the sequence.
Looking at the given sequence: 22, 18, 14, 10, 6, we can see that each term is decreasing by 4.
The general formula for finding the nth term of a linear sequence is:
nth term = First term + (n - 1) * Common difference
In this case, the first term is 22 and the common difference is -4 (as the sequence is decreasing by 4 each time).
Using the formula, we can find the 15th term as follows:
15th term = 22 + (15 - 1) * (-4)
= 22 + 14 * (-4)
= 22 - 56
= -34
So, the 15th term of the given linear sequence is -34.