The length of a picture frame is 8 inches more than the width. For what values of x is the perimeter of the picture frame greater than 152 inches
didn't we just do one of these?
assuming that x is the width (which you do not say),
2(x + x+8) >= 152
>35
no no no >34
To find the values of x for which the perimeter of the picture frame is greater than 152 inches, let's break down the problem step by step.
Let's assume that the width of the picture frame is x inches. According to the given information, the length of the picture frame would be 8 inches more than the width, so it would be (x + 8) inches.
The perimeter of the picture frame can be calculated by adding up all the sides. Since it's a rectangle, the formula for the perimeter is as follows:
Perimeter = 2*(length + width)
Substituting the values, we have:
P = 2*((x + 8) + x)
P = 2*(2x + 8)
P = 4x + 16
Now we need to find the values of x for which the perimeter is greater than 152 inches:
4x + 16 > 152
To solve this inequality, we need to isolate x:
4x > 152 - 16
4x > 136
Dividing both sides of the inequality by 4:
x > 34
Therefore, the width of the picture frame (x) must be greater than 34 inches for the perimeter to be greater than 152 inches.