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Simpligy (4sin^2xcos^2x)/(sin2xcos2x)

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asked by Anonymous
3 years ago
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huh. recall that sin2x = 2 sinx cosx

so you have
(sin2x)^2 / (sin2x cos2x) = sin2x/cos2x = tan2x

answered by oobleck
3 years ago
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Did you know?

Did you know that the expression simpligy (4sin^2xcos^2x)/(sin2xcos2x) can be simplified using trigonometric identities? By applying the double angle formula for sine and cosine, we can rewrite the expression as (4sin^2x(1 - sin^2x))/(2sinxcosx(1 - 2sin^2x)). This further simplifies to (4sin^2x - 4sin^4x)/(2sinxcosx - 4sin^3xcosx). Consequently, canceling out common factors, we obtain the simplified form of 2sinx - 2sin^3x/cosx - 2sin^2xcosx. This sort of simplification helps us to reduce complex expressions and reveal underlying patterns and relationships in mathematics.

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