Two ships leave port at 9 A.m. One
is headed N53°W and is travelling at
12 mph. The other is travelling at
s mph, with heading S67°W. How far
apart are the two ships at 11 a.m.?
ship 1 goes 24 miles
north = 24 cos 53
west = 24 sin 53
ship 2 goes 2 s miles
north = - s cos 67
west = s sin 67
north difference = 24 cos 53 + s cos 67
west difference = 24 sin 53 - s sin 67
difference = sqrt (north diff^2 + west diff^2)