Ron puts all his nails into 2 large boxes and 6 small boxes. There are 20 more nails in one large box than one small box. The number of nails in the 2 large boxes was 1/2 as many as the number of nails in the 6 small boxes. Find the number of nails in 1 large box.
1L = 1 large box
1S = 1 small box
1L = 1S + 20
2L = 2S + 40
6S = 2 x (2S + 40)
6S = 4S + 80
2S = 80
1S = 40
1L = 40 + 20 = 60
One large box has 60 nails
60 I hope this helps am I right anyone?
To find the number of nails in one large box, let's break down the information given step by step:
Let's assume the number of nails in one small box is "x".
According to the problem, there are 20 more nails in one large box than in one small box. So the number of nails in one large box can be represented as "x + 20".
The problem also states that the number of nails in the 2 large boxes is half as many as the number of nails in the 6 small boxes. So, we can set up the equation:
2(x + 20) = (6x)
Expanding the left side of the equation:
2x + 40 = 6x
Now, let's isolate the x variable by subtracting 2x from both sides:
40 = 4x
Dividing both sides by 4 to solve for x:
10 = x
So, the number of nails in one small box (x) is 10.
To find the number of nails in one large box (x + 20):
10 + 20 = 30
Therefore, the number of nails in one large box is 30.