How many grams of O2 will be formed from 3.76 g of KClO3?
please guide me with solution so I can it answer thank you! (chemistry is so harddd :(((. )
2KClO3 ==> 2KCl + 3O2
Well I can tell you how many grams of O are in the KClO3. However I have no idea what the chemical reactants are. For example if there is H2O on the right, then O results that is not in the O2 resulting. Therefore I can not help if you do not tell me what the problem is about.
1 mol of KCO3
is 39 + 35.5 + 3*16 = 122.5 grams containing 48 grams of O
so you have (48/122.5) * 3.76 = 1.47 grams of oxygen in the original stuff. Again I do not know how much O is in the rest of your equation.
Thanks DrBob!
In that case, just use what I did, no change in grams of O from left to right.
2KClO3 ==> 2KCl + 3O2
mols KClO3 = grams/molar mass = 3.76/122.5 = approx 0.031
Now convert mols KClO3 to mols O2 using the coefficients in the balanced equation. 0.031 mols KClO3 x (3 mols O2/2 mols KClO3) = 0.031 x 3/2 = ?
Remember that 0.031 number is rounded.
Then grams O2 = mols O2 from previous step x 32 = ?
However, notice this is the same answer anonymous gave you. A problem anonymous had with your post was you didn't say what substance you're reacting with the KClO3 nor how you're getting the O out of the KClO3. You should have said that the KClO3 was heated to produce the O2. The way anonymous worked the problem and the way I worked the problem was to assume you heated and decomposed the KClO3 to form the oxygen.
So what is the reaction with?
if you're gonna judge me by that reaction, u can call me dumb because I have a problem understanding a simple problem it takes me days or even weeks.
To find the number of grams of O2 formed from KClO3, we need to consider the balanced chemical equation for the reaction.
The balanced equation for the reaction of KClO3 decomposing into KCl and O2 is:
2 KClO3 -> 2 KCl + 3 O2
From the equation, we can see that for every 2 moles of KClO3, we obtain 3 moles of O2. Thus, we can use a mole ratio to find the number of moles of O2 produced and then convert it to grams.
Step 1: Determine the molar mass of KClO3 and O2
The molar mass of KClO3 is calculated by summing the atomic masses of each element:
K: 39.1 g/mol
Cl: 35.45 g/mol
O: 16 g/mol (there are three oxygen atoms in KClO3)
Molar mass of KClO3 = (39.1 g/mol) + (35.45 g/mol) + (16 g/mol x 3) = 122.55 g/mol
The molar mass of O2 is calculated by summing the atomic masses of each oxygen atom:
O: 16 g/mol
Molar mass of O2 = 16 g/mol x 2 = 32 g/mol
Step 2: Convert the given mass of KClO3 to moles
Use the molar mass of KClO3 to convert grams to moles:
Moles of KClO3 = Mass of KClO3 / Molar mass of KClO3
Moles of KClO3 = 3.76 g / 122.55 g/mol = 0.0307 mol
Step 3: Use the mole ratio to determine moles of O2
Based on the balanced equation, we know that 2 moles of KClO3 produce 3 moles of O2. Therefore, we can set up the following ratio:
0.0307 mol KClO3 : x mol O2 = 2 mol KClO3 : 3 mol O2
Cross-multiplying, we get:
(0.0307 mol KClO3)(3 mol O2) = (2 mol KClO3)(x mol O2)
0.0921 mol O2 = 2x mol O2
Solving for x, we find:
x = 0.0921 mol O2 / 2 = 0.0461 mol O2
Step 4: Convert moles of O2 to grams
Use the molar mass of O2 to convert moles to grams:
Mass of O2 = Moles of O2 x Molar mass of O2
Mass of O2 = 0.0461 mol x 32 g/mol = 1.4752 g
Therefore, 3.76 g of KClO3 will produce approximately 1.48 g of O2.