How many grams do 5.1×1023 atoms of argon
weigh?
6.023E23 atoms of Ar (that's one mole) have a mass of 39.9 grams so
39.9 g x (5.1E23/6.023E23) = ? grams.
Oh, don't be so 'argon' about it! The atomic weight of argon is approximately 39.95 grams per mole. So, to find the weight of 5.1×10^23 atoms of argon, we need to do some math. Let me just grab my calculator... or maybe I should call it a "calc-humulator"! Anyway, after a few calculations, the weight would be approximately 0.013 grams. That's like a tiny, invisible argon speck. Hope that answers your question with a humorous twist!
To find the weight, or mass, of 5.1×10^23 atoms of argon, we need to use the molar mass of argon and Avogadro's number.
1. Determine the molar mass of argon: The molar mass of argon (Ar) is approximately 39.95 grams per mole.
2. Convert the given number of atoms to moles: Divide the given number of atoms (5.1×10^23) by Avogadro's number (6.022×10^23 atoms per mole):
5.1×10^23 atoms / 6.022×10^23 atoms/mol = 0.848 moles
3. Calculate the weight (mass) using the molar mass:
0.848 moles × 39.95 grams/mole ≈ 33.90 grams
Therefore, 5.1×10^23 atoms of argon weigh approximately 33.90 grams.
To determine the weight of 5.1×10^23 atoms of argon, we need to take into consideration the molar mass of argon and Avogadro's number.
1. Look up the molar mass of argon:
The molar mass of argon, Ar, is approximately 39.95 grams/mole.
2. Calculate the number of moles:
To find the number of moles, we divide the given number of atoms by Avogadro's number:
Number of moles = number of atoms / Avogadro's number
Number of moles = 5.1×10^23 atoms / 6.022 × 10^23 atoms/mole
Number of moles = 0.846 moles
3. Calculate the weight:
Weight = number of moles × molar mass
Weight = 0.846 moles × 39.95 grams/mole
Weight = 33.8 grams
Therefore, 5.1×10^23 atoms of argon weigh approximately 33.8 grams.