How many minutes would be required for a 269.0 W immersion heater to heat 292.0 g of water from 16.8°C to 97.4°C?
heat needed = q = mass H2O x specific heat H2O x (Tfinal-Tinitial)
q = 292.0 g x 4.184 J/g*c x (97.4 - 16.8) = approx 98,000 Joules but that's just an estimate. You need to recalculate this and all of the numbers that follow.
1 watt = 1 joule/sec
watt x sec = joules
269.0 watt x sec = approx 98,000 J
sec = ? and convert to minutes. Post your work if you get stuck.