Percentage mass of sodium in sodium trioxonitrate(v) Na=23, N=14,O=16
Is It, 23+14 +48=85
23/85*100
14/85*100
16/85*100
Any answers🤨😁
Anyone😥
Someone please give me an answer
Is the answer to the question correct
Any anwers
No one is answering me
NaNO3. molar mass NaNO3 is 85.
So (23/85)*100 = ?%Na but I would prefer you name NaNO3 simply sodium nitrate.
To determine the percentage mass of sodium in sodium trioxonitrate(V), you need to calculate the molar mass of sodium trioxonitrate(V) and then find the mass contribution of sodium within the compound.
1. Start by calculating the molar mass of sodium trioxonitrate(V) by summing the atomic masses of the elements present:
Molar Mass = (Atomic mass of Na) + (Atomic mass of N) + 3 × (Atomic mass of O)
Molar Mass = (23) + (14) + 3 × (16)
Molar Mass = 85 g/mol
2. Determine the mass contribution of sodium within the compound:
Mass of sodium = (Atomic mass of Na) / (Molar Mass of sodium trioxonitrate(V)) × 100%
Mass of sodium = (23) / (85) × 100%
Mass of sodium = 27.06%
Therefore, the percentage mass of sodium in sodium trioxonitrate(V) is approximately 27.06%.