the current (L) in im amperes varies inversely as the resistance R in ohms ,if the the current is 30 amperes when the resistance is 3 ohms,what is the current when the resistance is 6 ohms
You want L such that
6L = 3*30
To solve this problem, we need to use the concept of inverse variation. Inverse variation means that as one variable increases, the other variable decreases, and vice versa, while their product remains constant.
Let's denote the current as I and the resistance as R. According to the given information, we know that:
Current (I) varies inversely as Resistance (R)
Mathematically, this can be represented as:
I ∝ 1/R
Or,
I = k/R
Where k is the constant of variation.
To find the value of k, we can use the given information: when the current is 30 amperes, and the resistance is 3 ohms. Plugging these values into the equation:
30 = k/3
To isolate k, we can multiply both sides by 3:
90 = k
Now that we have the value of k, we can use it to find the current (I) when the resistance (R) is 6 ohms:
I = k/R
Substituting the values:
I = 90/6
Simplifying:
I = 15
Therefore, when the resistance is 6 ohms, the current is 15 amperes.